2^2+3x-7=x^2+5x+39

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Solution for 2^2+3x-7=x^2+5x+39 equation: 



2^2+3x-7=x^2+5x+39

We move all terms to the left:

2^2+3x-7-(x^2+5x+39)=0

We add all the numbers together, and all the variables

3x-(x^2+5x+39)-3=0

We get rid of parentheses

-x^2+3x-5x-39-3=0

We add all the numbers together, and all the variables

-1x^2-2x-42=0

a = -1; b = -2; c = -42;
Δ = b2-4ac
Δ = -22-4·(-1)·(-42)
Δ = -164
Delta is less than zero, so there is no solution for the equation

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